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the odds of loosing your seedphrase multiply with the amount of seedphrase required.
The probability that A looses their seed phrase, p(A) > p(A) * p(B)
Or not?
No, that would be true if you only need 1 of the 2 Multi-Sig.
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The probability that A looses their seed phrase, p(A) > p(A) * p(B)
Or not?