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41 sats \ 11 replies \ @0xbitcoiner 10 Oct
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132 sats \ 1 reply \ @WeAreAllSatoshi 10 Oct
Wouldn’t it be A^2, not 2A?
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21 sats \ 0 replies \ @0xbitcoiner 10 Oct
I was starting to think no one was going to speak up! 🤠
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32 sats \ 8 replies \ @Undisciplined 10 Oct
Get out of my notes
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242 sats \ 7 replies \ @0xbitcoiner 10 Oct
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64 sats \ 1 reply \ @south_korea_ln OP 11 Oct
This is indeed the answer. I will write out the equations when I have a bit more time.
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0 sats \ 0 replies \ @Bell_curve 10 Nov
Can you write out some of the equations? pretty please lol
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232 sats \ 3 replies \ @Undisciplined 10 Oct
Good job!
I finally got it. It took me a while to see that E = 3/4 B.
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58 sats \ 2 replies \ @0xbitcoiner 10 Oct
I don't remember needing this! To be honest, I'm not entirely sure the result is correct 🤠
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28 sats \ 1 reply \ @Undisciplined 10 Oct
There may have been other ways to incorporate that information, but I ended up with the same answer as you.
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27 sats \ 0 replies \ @0xbitcoiner 10 Oct
Right! So math is all about rules, but sometimes there are sneaky shortcuts. I like it!
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0 sats \ 0 replies \ @Bell_curve 10 Nov
what is the answer? what is the key to the problem that I am not seeing?
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21 sats \ 0 replies \ @Scroogey 10 Oct
If you add a horizontal line where green touches red, and a vertical line where blue touches red, you get
The rectangles double the respective triangles' areas.
The answer is 5+4+3 minus the area of the top-left x.
But I couldn't solve that :(
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21 sats \ 0 replies \ @SimpleStacker 10 Oct
Following on this comment, #716461, I gave myself 5 minutes to try and solve the puzzle. I couldn't do it :(
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0 sats \ 0 replies \ @Bell_curve 11 Nov
solution:
you can also eye ball it
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0 sats \ 2 replies \ @Undisciplined 10 Oct
Do we know anything about the full shape?
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48 sats \ 1 reply \ @south_korea_ln OP 10 Oct
It's a square. I started writing it's a square of side $a$ and then realized the value of $a$ didn't matter, so deleted that. I thus inadvertently also deleted the information about it being a square. Mea culpa.
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19 sats \ 0 replies \ @Bell_curve 11 Nov
I think it works for any rectangle
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