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134 sats \ 0 replies \ @supertestnet OP 26 Mar \ parent \ on: Hedgehog: A protocol for asynchronous layer two bitcoin payments bitcoin
if Alice started with 10k sats, sent some money to Bob, and then closed, she tries to close with the prior state (where she still has all 10k sats), because she can't close with the latest state, due to only having 1 signature where 2 are needed. But that is why she has to wait 5 blocks (which should be more in production): during that time, Bob can set things right by running hedgehog.bob_penalize(). If Alice merely tried to finalize state X-1, nothing bad happens to her, Bob can only create the latest state (X). But if she broadcasted X-2, or any other state, Bob can take everything