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145 sats \ 0 replies \ @Brunswick 3 Oct 2022
The mantissa (the decimal part as opposed to the exponent part) of a 64bit floating point number safely holds 21x10^14 (sats) and leaves enough overhead to add or subtract two values without overflow. This appears to be the reasoning given to by this article.
Log10(21x10^14)/log10(2) = 50.9 bits
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145 sats \ 4 replies \ @_musallwah 3 Oct 2022
Interesting read
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0 sats \ 2 replies \ @Brunswick 3 Oct 2022
Interesting comment
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30 sats \ 0 replies \ @F 3 Oct 2022
I am whelmed by this.
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10 sats \ 0 replies \ @ek 3 Oct 2022
Interesting comment
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0 sats \ 0 replies \ @F 3 Oct 2022
Interesting is an illegal word, you have to explain in other words what unique quality the reading was.
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