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0 sats \ 4 replies \ @BallLightning 5h \ parent \ on: Dumping a fork coin doesn't crash its price bitcoin
Hm... If you don't count unfilled orders to the volume, then what you said about the volume of coins being sold being bigger to the volume of coins being is impossible. If you sell a coin, someone else buys it. So every coin sold is simultaneously bought by the counterparty of the trade. So sold and bought coin volume is always exactly the same. No matter how the trade was accomplished.
What's on the other side of the trade @BallLightning ?
1 coin sold for $500
1 coin sold for $495
1 coin sold for $490
1 coin sold for $480
You can do it backwards of course
$500 buys 1 coin
$495 buys 1 coin
$490 buys 1 coin
$480 buys 1 coin
There are 4 coins being bought/sold and $1965 dollars being bought/sold
If the volume of coins is greater than the volume of dollars, the price goes down. If the volume of dollars is greater than the volume of coins, the price goes up.
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Volume of dollars compared to volume of coons? This makes even less sense.
About who is in the other side? In order for you to have a sell order for one coon fulfilled, there mist exist a buy order for one coin to match. The person or entity holding the matching order is "the other side".
You always sell coins to someone. This someone is "the other side".
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This isn't a slave trade. You aren't trading people here. You're trading coins and dollars. I'm done wasting sats on you and I'm ashamed of engaging with a troll for this long
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What? Even if you were trading slaves the same still applies. You need a counterparty to your trade.
But i have no idea where these slaves came to your mind. Do you thought the counterparty is a slave?
Anyway, you are either deliberately hostile for no reason or you really can't grasp the concept that every trade has a seller or a buyer. The good thing is that my comments will also be seen by other people.
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