I was researching some obscure Bitcoin historic things, and I noticed that this address shows different values on the 2 different block explorers.

How could this be, since the blockchain is meant to be the same for everyone?
Has the node of one of these explorer went bad?
- Blockchain.com: https://www.blockchain.com/explorer/addresses/btc/1Jhk2DHosaaZx1E4CbnTGcKM7FC88YHYv9
- mempool.space: https://mempool.space/address/1Jhk2DHosaaZx1E4CbnTGcKM7FC88YHYv9
Maybe now is relevant to tell you where I got these addresses from?
Weeeel, I initially was looking at this TX
- Blockchain https://www.blockchain.com/explorer/transactions/btc/d71fd2f64c0b34465b7518d240c00e83f6a5b10138a7079d1252858fe7e6b577
- mempool: https://mempool.space/tx/d71fd2f64c0b34465b7518d240c00e83f6a5b10138a7079d1252858fe7e6b577
Now things look a bit better, the amounts are the same, but now only the addresses differ.
In fact on mempool, it seems we have something that does not look like an adddress.
In fact that is a Public Key.
You see a Bitcoin address, itself is also a Public Key with a few extra operations on top, to make it a bit more human readable, and limit errors when passing around.
Another thing that may be less known is that in the very early days of Bitcoin(which is when the TX in question took place), you could send Bitcoins to another node using their IP address.
You would get someones IP, and connect to their node, and you node would as for a Public Key.
Since these were machines talking with each other they did not need not fancy human addresses.
So what ended up happening is that mempool.space is correctly showing and interpreting the Pub Keys as Pub Keys, while blockchain interprets the Pub Keys as addresses, and because of this you will get an address that is valid but it will be another address.
How so?
Well what makes an address valid is just the last step, and if the last step is applied to some piece of data(as seen in the royal fork graphical address generator) you will get a valid address.
But if you want the "correct" address you must apply these last steps to the correct piece of data.
Footnotes