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Yes, but you are talking about fee rate. Fee is not in fractions of sats
- By
feeI meansum_of_outputs-sum_of_inputs - By
fee rateI meanfee/tx_vsize
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minrelaytxfee specifies fee rate, not total fee.
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Yes
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Yes, but you are talking about fee rate. Fee is not in fractions of sats
fee I mean sum_of_outputs-sum_of_inputsfee rate I mean fee/tx_vsizeminrelaytxfee specifies fee rate, not total fee.
Yes
It is possible and happens all the time, as there is no txfee field in tx data structure, it's just (sum_of_inputs - sum_of_outputs) / tx_vsize.