noknees

no one tried it still? :/
is it too hard?

Let me drop some useful formula:

**Given:**
$$m=0.2\ \mathrm{kg}, h=10\ \mathrm{m}, b=0.4\ \mathrm{kg/s}, g=9.8\ \mathrm{m/s^2}$$

$$
k=\frac{b}{m}=\frac{0.4}{0.2}=2\ \text{s}^{-1}.
$$
Velocity:
$$
v(t)=\frac{g}{k}\big(1-e^{-kt}\big).
$$
Position (distance fallen after time (t)):
$$
y(t)=\int_0^t v(t')\ dt'=\frac{g}{k}t+\frac{g}{k^2}\big(e^{-kt}-1\big).
$$

$$
= \frac{g}{k}t+\frac{g}{k^2}\big(e^{-kt}-1\big)=h.
$$

now just plug in numbers...