(circles have radii of r, 2r, and 3r)
Not really any trick today, just some basic application of formulae.
Previous iteration: #699554
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(circles have radii of r, 2r, and 3r)
Not really any trick today, just some basic application of formulae.
Previous iteration: #699554
Area of circle: πr^2
Under assumption that circles are split into thirds:
Outside band has area of biggest circle minus second biggest circle. Then divide by three.
3A = π(3r)^2 - π(2r^2) = (9π-4π)r^2 = 5πr^2
A = (5πr^2)/3
Answer = 5/27
P.s. @k00b when mathjax?
https://github.com/stackernews/stacker.news/issues/1436
@remindme in 13 hours
Yesterday's answer: #700787
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