(circles have radii of r, 2r, and 3r)
Not really any trick today, just some basic application of formulae.
Previous iteration: #699554
257 sats \ 0 replies \ @Rexdentron 26 Sep
Total area = π.(3r)² = π.9r²
Total area of the second circle = π.(2r)² = π.4r²
| Yellow area | Total area - ⅔ of the Total area - ⅓ of Total area of second circle |
| π.9r² - π.6r² - π. 4/3.r² | |
| (9 - 6 - 4/3) π.r² | |
| 5/3.π.r² |
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100 sats \ 0 replies \ @Murch 26 Sep
Area of circle: πr^2
Under assumption that circles are split into thirds:
Outside band has area of biggest circle minus second biggest circle. Then divide by three.
3A = π(3r)^2 - π(2r^2) = (9π-4π)r^2 = 5πr^2
A = (5πr^2)/3
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21 sats \ 1 reply \ @SimpleStacker 26 Sep
Answer = 5/27
P.s. @k00b when mathjax?
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206 sats \ 0 replies \ @south_korea_ln OP 26 Sep
https://github.com/stackernews/stacker.news/issues/1436
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0 sats \ 0 replies \ @WeAreAllSatoshi 26 Sep
@remindme in 13 hours
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0 sats \ 0 replies \ @south_korea_ln OP 26 Sep
Yesterday's answer: #700787
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