pull down to refresh

10 million random runs for some x between 0.0 and 1.0
    x=0.000 p=0.0000
    x=0.050 p=0.0499
    x=0.100 p=0.0999
    x=0.150 p=0.1499
    x=0.200 p=0.2001
    x=0.250 p=0.2500
    x=0.300 p=0.2999
    x=0.350 p=0.3499
    x=0.400 p=0.4000
    x=0.450 p=0.4501
    x=0.500 p=0.5001
    x=0.550 p=0.5501
    x=0.600 p=0.5999
    x=0.650 p=0.6498
    x=0.700 p=0.7001
    x=0.750 p=0.7498
    x=0.800 p=0.7999
    x=0.850 p=0.8500
    x=0.900 p=0.8998
    x=0.950 p=0.9501
    x=1.000 p=1.0000
Careful there, Faketoshi might not be able to understand your code snippet there, using unsigned integers (I presume that's what they are, I am not proficient in cpp)~~
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Well, that's one way of proving it :)
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