pull down to refresh

In the same vein as yesterday's problem, find the radius $r$ such that the area of the semicircle is the same as the area of the rectangle. The green region has an area of 10 (a.u.).
Previous iteration: #717118
Should there be an elegant solution or is it a big mess of radicals and inverse trig functions?
reply
Ok, for real this time. Let be the length of the rectangle.
We know and so
Moreover, it'll be useful to write:
The angle of the "pizza slice" that the green region covers is:
The area of the pizza slice is and the "height" of the green region is .
Thus:
Or:
Which gives
reply
I'm pretty sure I had the same answer, but I was trying to work it out analytically.
reply
I'm not as much of a fan of these brute force calculations, but once I start on something I find it very hard to stop...
I gave myself 15 minutes to do this, and I thought I had it, but it turns out I made a mistake. Ended up spending maybe 30-40 minutes on this problem... not great for my productivity today lol
reply
I don't think it simplified nicely, which isn't surprising when you put stuff like that into an inverse cosine.
reply
Yeah, i also usually prefer the ones that simplify nicely. Also because it's an indirect confirmation one is on the right track.
reply
It feels like a better puzzle when the answer comes out nice and simple.
reply
The green area is half a circle segment with height h.
The area of the rectangle is r*(r + r - h).
The area of the semicircle is (pi * r^2) / 2.
Since they are equal, you get h = 2*r - (pi * r)/2
Insert that h into the circular segment area based on height h formula and you get
reply
the reason this would take a while for me is that i like to derive the formulas from scratch for such problems... otherwise i trust not verify, haha.
reply
sometimes being good at math is knowing that someone else derived the formula you need, and knowing where to find that formula.
reply
yes, it's a process... i have the stamina and interest to relearn geometry, because i have a dream to build in stone, make true masonry great again.
i actually ran into a real mason recently. he retired and started making canvas art instead, based on his work as a mason. very intricate, never seen anything like it.
reply
That's a very cool reason to want to learn geometry. I wish you luck in your pursuits!
reply
Nice find, didn't even though there was a formula available for this on Wikipedia
reply
This is another level. I'm not even going to try!
reply
reply
I'm just not going to try it because I've got a headache and I don't want to make it worse! Today is Friday ... Ahahaha
reply
We say 불금 here, fire-friday... people getting drunk and letting free after a hard week of work. No alcohol for me today, though...
reply
this? 🤠
I don't need a lot of alcohol to have fun. Two whiskies is enough for the whole night! Ahhahaha
reply
Social media campaign from Hana Bank it seems.
A modern take on 불금 where one prefers staying in with some fried chicken and beer (chimaek, 치맥) to watch a Korean drama on the laptop~~
reply
Ah ok! Or read Han Kang's works. #717216
reply
Missed that post. Tnx for linking. Enjoy, time for me to sleep here.
i have a bet with an older friend that i will pass the differential calculus exam when i reach the age at which he failed it (about 40yo), after having the same amount of study time. i shall also pass the integral calculus exam, because it's not about the age, but the amount of cobwebs in the brain.
reply
We should have a button for MathJax syntax like the markdown instructions button in the upper right of the text area input. I am familiar with markdown, but not MathJax.
reply
deleted by author
reply
wait I made a mistake... urk
reply
deleted by author
reply