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The area of the outer big square is (a + b)^2 = 100.
The area of the inner small square is a^2 + b^2 (from Pythagoras on the triangles).
To calculate the inner square area, you take the outer square area, and subtract the area of the triangles:
a^2 + b^2 = (a + b)^2 - 2(a * b) = 100 - \frac{4*21}{2} = 58
I love how the same algebraic solutions can have a very interesting geometric interpretation. Math is so beautiful
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Yea, that is pretty cool!
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