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Using log laws:
log(a) + log(b) + log(c) = log(abc)
Therefore,
log(abc) = log(a + b + c)
abc = a + b + c
Where,
abc, a, b, c > 0
So from here you just rearrange in terms of a:
a = (b + c) / (bc - 1)
...and pick any value for b and c which are greater than 0. Such as:
b = 2, c = 1
a = (2 + 1) / (2*1 - 1) = 3
__@_'-'
Interesting cases:
a = b = c = root(3)
a = b = (1 + root(5))/2, c = 2
Using log laws:
log(a) + log(b) + log(c) = log(abc)
Therefore,
log(abc) = log(a + b + c)
abc = a + b + c
Where,
abc, a, b, c > 0
So from here you just rearrange in terms of a:
a = (b + c) / (bc - 1)
...and pick any value for b and c which are greater than 0. Such as:
b = 2, c = 1
a = (2 + 1) / (2*1 - 1) = 3
__@_'-'