Yes, 7 is correct: https://stacker.news/items/731084/r/south_korea_ln

south_korea_ln

I think I get the logic of it but I don't have a proof.

A = G+H+I
F = B+E+I
J = B+C+G

That means they are each at least 6 and none of B, C, E, G, H, or I can be larger than 6, which means they make up 1-6 in some order.

Then, it must be impossible to arrange them such that any of A, F, or G are equal to seven without one of them being greater than 10.

That leaves 7 for D.

Undisciplined

science

[Daily puzzle] Another MSM puzzle

I brute forced it

```
import numpy as np
import itertools

A,B,C,D,E,F,G,H,I,J = 0,1,2,3,4,5,6,7,8,9
x = np.arange(1,11)

for p in itertools.permutations(x, 10):
    red = p[A]+p[B]+p[C]+p[D]+p[E]
    yellow = p[C]+p[D]+p[F]+p[G]+p[H]
    green = p[B]+p[C]+p[D]+p[E]+p[G]+p[H]+p[I]
    blue = p[D]+p[E]+p[H]+p[I]+p[J]
    if (red==yellow) and (red==green) and (red==blue):
        break

p
```

D = 7