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I think zero is generally considered even as it can be divided by two without remainder.
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Since the number zero is even, both are correct!
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Yes, there should be two valid solutions.
I'll post the reasoned solution to this problem at the same I post the next problem tomorrow.
I like brute force solving problems in my daytime job. It's sometimes so much faster.
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1
, of the digit 1 is2
, of the digit 2 is3
, of the digit 3 is2
, of even numbers is5
, <---- of odd numbers is6
, and of prime numbers is7
.1
, of the digit 1 is2
, of the digit 2 is3
, of the digit 3 is2
, of even numbers is6
, <---- of odd numbers is5
, and of prime numbers is6
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