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Saw the hint before trying to solve all by myself :((
k = sqrt(7-sqrt(7+k)) k^2 = 7-sqrt(7+k) sqrt(7+k) = 7-k^2 7+k = (7-k^2)^2 7+k = 49 - 14k^2 + k^4 k^4 - 14k^2 - k + 42 = 0
You can probably solve it analytically, but I quickly guessed k=2 looking at the numbers.
You can use Polynomial long division to find the factors of this quartic equation...
But guessing in this case works too, and is faster :)
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For the record, and are two roots. The last two roots can easily be found from the remaining quadratic equation. can be discarded due to being a negative number whereas a root is always positive. As for the two roots from the quadratic equation, one is negative, whereas the other one is larger than which is in contradiction with the initial root problem, so both can be discarded too. Only is a valid solution to the initial problem.
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