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Saw the hint before trying to solve all by myself :((
k = sqrt(7-sqrt(7+k))
k^2 = 7-sqrt(7+k)
sqrt(7+k) = 7-k^2
7+k = (7-k^2)^2
7+k = 49 - 14k^2 + k^4
k^4 - 14k^2 - k + 42 = 0
You can probably solve it analytically, but I quickly guessed k=2 looking at the numbers.
You can use Polynomial long division to find the factors of this quartic equation...
But guessing in this case works too, and is faster :)
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For the record, 2 and -3 are two roots. The last two roots can easily be found from the remaining quadratic equation. -3 can be discarded due to being a negative number whereas a root is always positive. As for the two roots from the quadratic equation, one is negative, whereas the other one is larger than \sqrt{7} which is in contradiction with the initial root problem, so both can be discarded too. Only 2 is a valid solution to the initial problem.
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