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24 sats \ 1 reply \ @Murch 14 Mar
2*x + 5*(16-x) = 50
2x + 80 - 5x = 50
30 - 3x = 0
30 = 3x
x = 10
Ergo, 10 * $2 and (16-10 = 6) * $5
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42 sats \ 0 replies \ @cryotosensei OP 15 Mar
We don’t teach our pri school kids to use algebra to solve word problems, but of course, your method is elegant.
I gotta teach my son to use algebra next time!
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24 sats \ 2 replies \ @0xbitcoiner 14 Mar
10 notes x 2$ = 20$
6 notes x 5$ = 30$
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21 sats \ 1 reply \ @cryotosensei OP 15 Mar
I bet you kinda rolled your eyes at the inane things my education system is testing kids haha
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0 sats \ 0 replies \ @0xbitcoiner 16 Mar
9 years old kids?
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24 sats \ 1 reply \ @flat24 14 Mar
I guess you only have a 5$ ticket, it has 32$ in 2$ bills and the remaining (13) that is not mentioned will be 1$ tickets
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0 sats \ 0 replies \ @cryotosensei OP 15 Mar
Effort for trying!
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24 sats \ 1 reply \ @suraz 14 Mar
6
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0 sats \ 0 replies \ @cryotosensei OP 15 Mar
Good job
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24 sats \ 1 reply \ @south_korea_ln 14 Mar
Did you post anonymously on that forum?~~
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0 sats \ 0 replies \ @cryotosensei OP 15 Mar
No.
I used my real name to post my blog articles to drive traffic to my blog haha.
I took a screenshot of that question because I wanted to consolidate concepts about money on my blog haha
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0 sats \ 0 replies \ @kurszusz 16 Mar
If don't want to use algebra, just logical thinking...
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The sum of $5 notes needs to end in 0 (not in 5), because the sum of $2 notes can't be end in impair number. => we have even-numbered $5 notes => we have even-numbered $2 notes.
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possible variations for a $5 notes (to make it less than 50): A. 2 pieces: $10 B. 4 pieces: $20 C. 6 pieces: $30 D. 8 pieces: $40 E. 10 pieces: $50
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Based on the 2nd point => the sum of $2 notes need to end also in 0. => the possible variations: a. 5 pieces: $10 b. 10 pieces:$20 c. 15 pieces: $30 d. 20 pieces: $40 e. 25 pieces: $50
For a total amount of $50, we need:
- A,d
- B, c
- C, b
- D, a
- E
- e Of the above 6 options, only in one case is the total number of banknotes 16 (C, b)
The answer: Harry have 6 pieces of $5 notes.
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