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The two circles and with radii of 1 are tangent with each other and with the horizontal line at the bottom. Circle is inscribed with a maximum possible radius inside , , and the horizontal line. , ,... are successively inscribed following the same rule maximizing their radius.
Find the diameter of a circle .
Previous iteration: #720410 (quite a few different valid solutions were found for this one, congrats~~)
For looking at the right triangle
Pythagoras says
which means the diameter of is .
This can be repeated of giving and giving etc.
I don't yet have the generic formula for
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Looks good. I'm not sure about your value for though.
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For
For
Diameter is twice that, so
No?
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106 sats \ 1 reply \ @Scroogey 14 Oct
That would give diameters
For the sequence of divisors there are multiple candidates
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This is a great website. Didn't know about it. Made me check out the infamous https://oeis.org/A000127 sequence, for which there seem to be many more cases showing this unexpected change from 32 to 31.
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Aren't you using the same symbol to denote the different radii of (as in the drawing) and (as in the right-hand side of the formula below)? And same comment for the subsequent equation?
For
For
I used a different approach to solve this problem (I'll post it as a solution with the next iteration), but that one gives me for .
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For
(the top-left corner of the triangle is supposed to be the center of )
The hypotenuse is 1 + , where denotes the radius of .
The horizontal leg is simply 1 (this is true for all ).
The vertical leg is minus the sum of all diameters and minus of .
So, Pythagoras gives of .
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Ok got it. This seems correct. I'll have to figure out why my approach is giving a different result. I likely must have applied it incorrectly. Please don't spend more time on this, I'm assuming the error must be on my side at this point.
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You're right, I incorrectly applied Descartes. 1/12 is correct. My bad...
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Oh, neat, I didn't know about Descartes' theorem!
So you're calculating
where curvature is (the inverse of the radius).
If I pick , and to calculate
Now we can simply repeat with , and to calculate
So radius or diameter
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And I guess a direct formula for circle could be
Yes, exactly.
a fractal generated by starting with a triple of circles, each tangent to the other two, and successively filling in more circles, each tangent to another three.
I'll check my notes tomorrow.
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