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I stumbled on this nice little puzzle the other day. I'll link to the source tomorrow when sharing the answer. Until then, have fun :)
Find all the possible ways, if any exist, to fill in the three blanks to make all three statements true.
Previous iteration: #726159 (partial proof for special case in #728029)
335 sats \ 1 reply \ @Scroogey 17 Oct
If you allow words instead of numbers as solutions: odd, irrational, and odd.
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Even better than what Randall Munroe had in mind (#731084).
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Do the 1, 2, and 3 that label each panel count?
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I hadn't thought of that. That way the solution could be something else. Let's give it a try!
ā–£ 1 = a ā–£ 2 = b ā–£ 3 = c
a = b + c + 5 b = āˆš(ab3) c = min(a, b , 1)
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That's up to you to decide šŸ˜œ
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  1. 0
  2. 0
  3. 0
:)
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Trivial solutions are solutions too ;)
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There is a unique positive integer solution, assuming we include the panel identification numbers.
Solving it gives:
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58 sats \ 0 replies \ @nym 17 Oct
Panel 1: 1.618 Panel 2: 1.272 Panel 3: 1
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Here a link to a link to the answers: #731084
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deleted by author
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