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I hadn't thought of that. That way the solution could be something else. Let's give it a try!
▣ 1 = a▣ 2 = b▣ 3 = c
a = b + c + 5b = √(ab3)c = min(a, b , 1)
I hadn't thought of that. That way the solution could be something else. Let's give it a try!
▣ 1 = a
▣ 2 = b
▣ 3 = c
a = b + c + 5
b = √(ab3)
c = min(a, b , 1)