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500 sats \ 8 replies \ @Scroogey 29 Oct \ on: [Daily puzzle] Fill in the blanks science
Brute force finds two solutions:
1 2 3 2 5 6 7
1 2 3 2 6 5 6
I think it's an impossible problem to solve!
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This would be an impossible variant to this self-referential problem:
"In this sentence, the number of occurences of the digit 0 is ______, of the digit 1 is ______, of the digit 2 is ______, of even numbers is ______, of odd numbers is ______, and of prime numbers is ______."
(notice the omission of the digit 3 part)
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In this sentence, the number of occurences
of the digit 0 is
1,
of the digit 1 is 2,
of the digit 2 is 3,
of the digit 3 is 2,
of even numbers is 5, <----
of odd numbers is 6,
and of prime numbers is 7.In this sentence, the number of occurences
of the digit 0 is
1,
of the digit 1 is 2,
of the digit 2 is 3,
of the digit 3 is 2,
of even numbers is 6, <----
of odd numbers is 5,
and of prime numbers is 6.I'm considering that 0 is neither even nor odd
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I think zero is generally considered even as it can be divided by two without remainder.
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Since the number zero is even, both are correct!
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Yes, there should be two valid solutions.
I'll post the reasoned solution to this problem at the same I post the next problem tomorrow.
I like brute force solving problems in my daytime job. It's sometimes so much faster.
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