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1000 sats \ 1 reply \ @south_korea_ln 13m \ on: Christmas greeting card v2 [100x gift inside] bitcoin
Merry Christmas all and a happy New year. Let's be a little less polarised and a bit more understanding towards people who don't share our values and ideas. I've yet to meet the person that triggered me online who didn't turn out to be a nice person offline...
The obligations imposed on CASPs conflict with the rise of open-source technologies like the Lightning Network, Fedimint, and e-cash, which are permissionless, censorship-resistant, and provide strong privacy guarantees. These rapidly growing technologies are reshaping global transaction patterns, and by rejecting such transactions, EU-based CASPs risk losing market share and being outcompeted by non-European rivals operating under less restrictive frameworks. This regulatory approach may marginalise EU CASPs, pushing users toward unregulated alternatives outside the EU, thereby undermining the effectiveness of the AML/CFT framework. The result is not only a failure to meet regulatory objectives but also a weakening of the EU’s digital economy, innovation capacity, and global competitiveness in financial services.
Thanks for the general skepticism in the comments. Indeed, i did not go further than the inc.com article so it's hard to gauge how reliable this conclusion is. Hope I'll get to read the original article, if i get to it, back from my holidays.
Scientists led by Tobias Kippenberg at EPFL have now achieved the long-sought goal: They successfully prepared six mechanical oscillators in a collective state, observed their quantum behavior, and measured phenomena that only emerge when oscillators act as a group. The research, published in Science, marks a significant step forward for quantum technologies, opening the door to large-scale quantum systems.
Not fake news ;)
Just need to go beyond the headlines...
But yes, too much hype when people talk about quantum computers.
Mathematically, 20 million has an infinite number of divisors.
Does it? Usually, one considers integers as divisors.
I count ) divisors using
Sorry :)
How a little dip can completely change the odds for a prediction market...
Take heed, a characteristic single sat zap was just received.
@Scroogey's neurons are on the case...
Wow, 5 different stackers zapped this post within 5 minutes of posting this...
Did I just hit the optimal posting time (9 AM CST)?
I somehow missed this article linked in this yearly review. Putting it on my list of things I want to read ;)
Anyone might speak other languages with degrees of fluency, but they don't speak them natively
We can agree on this part :)
Wasn't sure anymore that I understood OP's intent after reading his response to my response, but seems like I did as you interpreted it in the same way.
Yes, it's all about understanding, comprehension and respect. I do speak several of the languages you speak, and I think you are pretty easy to understand when you do so. Especially because you manage to tone down your English accent.
For what it's worth, it's your native English that sounds most "comedic" to me, but that's because British English just does that to me ;)
Ha... I didn't know there was another word for voice and music.
Well, seems like I can't imagine voices or music either.
Similar articles came up here before, here one example: #631636
What do you mean by "fake accent"?
I imagine it's an attempt at trying to sound like a native (which is of course very hard to do when you're not native, hence the sometimes comedic effect) to be more understandable. I think that's a good habit.
As a side note, in Korea, Americans are notorious for standing out with their native American accent when talking Korean, while non-English natives tend to blend in slightly better when speaking Korean. A gross generalization of course.
By the way, I think Joe speaks several languages "natively" beyond English. I'm not sure though.
Nice video, I agree.
For the record, and are two roots. The last two roots can easily be found from the remaining quadratic equation. can be discarded due to being a negative number whereas a root is always positive. As for the two roots from the quadratic equation, one is negative, whereas the other one is larger than which is in contradiction with the initial root problem, so both can be discarded too. Only is a valid solution to the initial problem.